(1/x)+(1/x^2)

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Solution for (1/x)+(1/x^2) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/(x^2) = 0

x^-1+x^-2 = 0

t_1 = x^-1

1*t_1^2+1*t_1^1 = 0

t_1^2+t_1 = 0

DELTA = 1^2-(0*1*4)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)-1)/(1*2) or t_1 = (-1^(1/2)-1)/(1*2)

t_1 = 0 or t_1 = -1

t_1 = -1

x^-1+1 = 0

1*x^-1 = -1 // : 1

x^-1 = -1

-1 < 0

1/(x^1) = -1 // * x^1

1 = -1*x^1 // : -1

-1 = x^1

x = -1

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -1

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